2x^2-25x+3x^2-60=90

Solution for 2x^2-25x+3x^2-60=90 equation:

2x^2-25x+3x^2-60=90

We move all terms to the left:

2x^2-25x+3x^2-60-(90)=0

We add all the numbers together, and all the variables

5x^2-25x-150=0

a = 5; b = -25; c = -150;
Δ = b2-4ac
Δ = -252-4·5·(-150)
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5\sqrt{145}}{2*5}=\frac{25-5\sqrt{145}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5\sqrt{145}}{2*5}=\frac{25+5\sqrt{145}}{10}
$